Comments on: MySQL to JSON with PHP

By: GeoBob

GeoBob — Tue, 21 Jun 2011 11:40:29 +0000

I think there is an errant semicolon on line 31 of your code. I don’t think there should be a semicolon inside the quotation marks. Take it out, and you get JSON code that validates.

Thanks for your post! It’s been extremely helpful.

By: jocuri

jocuri — Mon, 13 Dec 2010 14:52:29 +0000

caleb, it tried your code, and is not working

By: Caleb Wright

Caleb Wright — Thu, 24 Sep 2009 16:37:17 +0000

PHP 5.2+ has a function called json_encode(). So you can shorten everything to this:

function mysql2json($mysql_result,$name) {
$result = array($name => array());
while ($row = mysql_fetch_assoc($mysql_result))
$result[$name][] = $row;
return json_encode($result);
}

(I haven’t tested it, but it should work).

By: Stephen McIntyre

Stephen McIntyre — Thu, 24 Sep 2009 08:00:56 +0000

One thing I’d suggest would be to add the line $count_names = count($field_names); after the line beginning with $rows = mysql_num… and refer all of your references to count($field_names) instead to the $count_names var.

Otherwise you call the count() function twice for every occurence of $x in each $y, which can add up, especially if you’re querying the number of fields and values in a database.

Otherwise, keep up the great posts, especially with PHP :)

By: Ransom Weaver

Ransom Weaver — Thu, 24 Sep 2009 00:38:21 +0000

Don’t forget AMFPHP’s great JSON gateway. If you have an AMFPHP service e.g. “getMyStuff” a call to the gateway will return a JSON version. Example:

function getMyStuff($usr,$pwd) {
// get the stuff with php from mysql
return $mySqlResult;
}

example JSON call:

http://somesite.com/amfphp/myservices/getMyStuff/myusrname/mypwd

You can also set this up to use POST vars instead of inline GET